Question

You throw a baseball (mass 0.145 kg) vertically upward. It leaves your hand moving at 12.0 m/s. Air resistance can be neglected. At what height above your hand does the ball have half as much upward velocity?

Answer 1

`h = 5.505\,m`

Step-by-step explanation:

Let assume that ball begins its movement at a height of zero. The height can be found by energy approach, to be precise, by Principle of Energy Conservation:

`(1)/(2)\cdot (0.145\,kg)\cdot (12\,(m)/(s) )^(2)= (1)/(2)\cdot (0.145\,kg)\cdot (6\,(m)/(s) )^(2)+(0.145\,kg)\cdot (9,81\,(m)/(s^(2)) )\cdot h`

`h = 5.505\,m`