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A wire 390 in. long is cut into two pieces. One piece is formed into a square and the other into a circle. If the two figures have the same area, what are the lengths of the two pieces of wire (to the nearest tenth of an inch)?

User Jamheadart
by
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2 Answers

7 votes

Answer:

Explanation:

Let x is the length of the square side.

We know: the two figures have the same area

<=>
x^(2) = π
r^(2) (r being radius)

<=> x =
√(II) r

perimeter square = 4x = 4*r*
√(II)

perimeter circle = 2*r*π

<=> 390 = 4*r*
√(II) + 2*r*π

<=> r = 29.16

=> perimeter square = 4*29.16*π

=> perimeter circle = 58.32π

User Srfrnk
by
8.6k points
2 votes

Explanation:

Below is an attachment containing the solution.

A wire 390 in. long is cut into two pieces. One piece is formed into a square and-example-1
A wire 390 in. long is cut into two pieces. One piece is formed into a square and-example-2
User Timofey
by
7.7k points

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