Question

Iron (III) oxide reacts with carbon monoxide producing iron metal and carbon dioxide. How much grams of iron is produced from 749 g of iron (III) oxide

Answer 1

389.48g of Fe

Step-by-step explanation:

This is a stoichiometric reaction. First write a balanced equation of reaction: Fe2O3+3CO==>2Fe+3CO2

Since Fe2O3 and Fe are concerned with, calculate there masses in the balanced equation

Taking Molar mass of Fe and O to be 26 and 16 respectively.

Fe2O3 = (2×26) + (3×16)

=100g/mol

2Fe = 2×26

= 52

Therefore 100g of Fe2O3 gave 52g

749g of Fe2O3 will give

749×52/100

= 389.48g of Fe