Question

Two circular loops of wire, each containing a single turn, have the same radius of 5.1 cm and a common center. The planes of the loops are perpendicular. Each carries a current of 1.5 A. What is the magnitude of the net magnetic field at the common center

Answer 1

`2.6135*10^-^5 T`

Step-by-step explanation:

Using the equation and Pythagorean theorem, we find that magnitude of the net magnetic field at the center of the two loops is expressed as:

`B_n=\sqrt{((N\mu_0I)/(2R))^2+((N\mu_0I)/(2R))^2}\\=√(2)((\N\mu_0I)/(2R))\\=(√(2)(1)(4\pi * 10^-^7/T.m/A)(1.5A))/(2.0(0.040m))\\=2.6135*10^-^5 T`

Hence, the net magnitude at the common center is
`2.6135*10^-^5 T`