Answer:
a) Increases.
b) Decreases.
c) Decreases.
d) Decreases.
e) Decreases.
Step-by-step explanation:
The forces acting on the box and the resolving of the forces are shown in the attached image to the question.
From the balance, the normal reaction = mg cos θ
a) The component of the gravitational force on the box, along the ramp is given by mg sin θ
As θ increases from 0, this component also increases (since sin θ increases)
b) At θ = 0, the frictional force is μN, but as θ gains in value, it becomes smaller.
Indicating a decrease in value as θ increases until the box slips.
c) the component of the gravitational force on the box, perpendicular to the ramp is mg cos θ and it decreases from the maximum at (mgcos 0 = mg) to mg cos θ.
d) The normal reaction = mg cos θ and this decreases from mg at 0 to whatever value as θ increases. Normal reaction decreases.
e) The maximum value fs, max of the static frictional force also decreases as θ increases. It decreases from (μmg cos 0) to (μmg cos θ) as θ goes from 0 to θ.