Question

A cylindrical specimen of this alloy having a length of 63 mm must elongate only 0.11 mm when a tensile load of 53,500 N is applied. Under these circumstances, what is the radius of the specimen (in mm)?

Answer 1

10.66mm

Step-by-step explanation:

Given that the elongation is
`\bigtriangleup l=0.11mm` and Length,
`l=63mm` and Tensile Strength,
`F=53500`, The longitudinal stress can be calculated as:

`\epsilon=(\bigtriangleup l)/(l)=0.11/63=1.746*10^-^3`

The value of strain-stress,
`\sigma=150MPa` corresponding to
`1.746*10^-^3`'

`\sigma=(F)/(A_o)\\150=(53500)/(\pi r_o^2)\\\\r_o=10.66mm`

Hence, the radius of the specimen is 10.66mm