The point (1, -3) is not a solution to system of given inequality
Solution:
Given system of inequalities are:
![y < x - 1 --------- eqn\ 1\\\\\ y > -x + 2 -------- eqn\ 2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/b86mxvyutjlfqran2mzo5agnjjc5ls2327.png)
We have to check if the point (1, -3) is a solution to system
Substitute (x, y) = (1, -3) in eqn 1 and eqn 2 and check if satisfies the inequality
Substitute (x, y) = (1, -3) in eqn 1
![-3 < 1 - 1\\\\-3 < 0](https://img.qammunity.org/2021/formulas/mathematics/middle-school/1iejjhaalq51jdeiwnl97jealb937r1cvt.png)
-3 is less than 0 is true
Substitute (x, y) = (1, -3) in eqn 2
![-3 > -1 + 2\\\\-3 > 1](https://img.qammunity.org/2021/formulas/mathematics/middle-school/bqxe3kis6ax3siga15pgqo0epnv4tu0cb1.png)
-3 greater than 1 is false
Therefore, the point (1, -3) is not a solution to system of given inequality