Question

A student connects a 300 kg container to a rope and pulley system and then connects the rope to a motor. If the student wants to lift the container 10.0 m in 2.0 min, what average power rating is required?

Answer 1

To develop this problem, we will apply the concepts related to Power, which is defined as the energy unit of a body per unit of time. Mathematically it can be written as,

`P = (E)/(t)`

In this case the Energy is equivalent to the potential energy accumulated by the body therefore,

`P = (mgh)/(t)`

Replacing with our data and taking the units to the International System we have to,

`P = ((300kg)(9.8m/s^2)(10))/((2min)((60s)/(1min)))`

`P = 245W`

Therefore the average power rating required is 245W