Question

A loudspeaker has a circular opening with a radius of 0.1158 m. The electrical power needed to operate the speaker is 27.0 W. The average sound intensity at the opening is 25.6 W/m2. What percentage of the electrical power is converted by the speaker into sound power

Answer 1

electrical power is converted by the speaker into sound power 17.25 %

Step-by-step explanation:

given data

radius = 0.1158 m

power needed = 27.0 W

average sound intensity = 25.6 W/m²

solution

we know sound intensity that is

I =
`(power)/(area)` ...................1

power = intensity × area

Power = 25.6 × 4 ×π×r²

Power = 25.6 × 4 ×π×0.1158²

power = 4.313 W

so here electric power % into sound power

=
`(4.313)/(25)` × 100

= 17.25 %