Question

A 600.0 mL sample of krypton is held at standard conditions. What volume does the gas occupy when the pressure is tripled and the temperature doubles

Answer 1

Answer: The volume when the pressure and temperature has changed is 400 mL

Step-by-step explanation:

To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.

The equation follows:

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

where,

`P_1,V_1\text{ and }T_1` are the initial pressure, volume and temperature of the gas

`P_2,V_2\text{ and }T_2` are the final pressure, volume and temperature of the gas

We are given:

`P_1=P_1\\V_1=600.00mL\\T_1=T_1\\P_2=3P_1\\V_2=?\\T_2=2T_1`

Putting values in above equation, we get:

`(P_1* 600mL)/(T_1)=(3P_1* V_2)/(2T_1)\\\\V_2=(600* P_1* 2T_1)/(T_1* 3P_1)=400mL`

Hence, the volume when the pressure and temperature has changed is 400 mL