Answer:
Read the explanation
Explanation:
I am sure you missed out the base while typing the question.
If the complete question is
![log_(3)(x + 5) = 2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/nluw7g3eiqwdjoajqzfk74niwk1gs6efrn.png)
Then taking antilogarithm or rewriting in exponential form gives:
![x + 5 = {3}^(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/c9hfxs9l0feogwwf80jpgsvoggb8e7gek4.png)
Or
![{3}^(2) = x + 5](https://img.qammunity.org/2021/formulas/mathematics/middle-school/q8d3avw54huc41zt2lfyssbyj3v5g0uw81.png)
But if the complete question is:
![log_(2)(x + 5) = 2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/t7pnsa5q1gjycwe97m1lmt0d9a5tg4iygx.png)
Then the equivalent form is
![{2}^(2) = x + 5](https://img.qammunity.org/2021/formulas/mathematics/middle-school/nsfdxhr68pu9pyy82lwi276ygus7r78uht.png)