Question

An astronaut lands on another planet and wishes to determine the acceleration due to gravity.the astronaut measure a period of 0.5m pendulum as being 3.2 seconds what is the acceleration due to gravity

Answer 1

1.927 m/s^2

Step-by-step explanation:

period = 2 pi sqrt ( l/g)

3.2 = 2 pi sqrt (.5/g) =1.927 m/s^2