C(-2,4) and D(-6,-1) what is length of CD

asked Sep 15, 2021 37.0k views

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5 votes

Answer:

6.40 units (3 s.f.)

Explanation:

distance between 2 points=
$\sqrt{(x2 - x1)^(2) + {(y2 - y1)}^(2) }$

Thus, length of CD

$= \sqrt{ {( - 2 + 6)}^(2) + {(4 + 1)}^(2) } \\ = \sqrt{{4}^(2) + 5^(2) } \\ = √(41) \\ = 6.40 \: \: (3 \: s.f.)$

Valeh Hajiyev answered Sep 22, 2021

7.2k points

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