Question

C(-2,4) and D(-6,-1) what is length of CD

Answer 1

6.40 units (3 s.f.)

Explanation:

distance between 2 points=
`\sqrt{(x2 - x1)^(2) + {(y2 - y1)}^(2) }`

Thus, length of CD

`= \sqrt{ {( - 2 + 6)}^(2) + {(4 + 1)}^(2) } \\ = \sqrt{{4}^(2) + 5^(2) } \\ = √(41) \\ = 6.40 \: \: (3 \: s.f.)`