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How much pure acid should be mixed with 3 gallons of a 20% acid solution in
order to get a 60% acid solution?

User Melih
by
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1 Answer

2 votes

Answer:

3 gallons

Explanation:

Let

x ----> the amount of pure acid (100% solution) in gallons

Remember that


100\%=100/100=1


20\%=20/100=0.20


60\%=60/100=0.60

we know that


(1)(x)+(0.20)(3)=(0.60)(x+3)

solve for x


x+0.60=0.60x+1.80


x-0.60x=1.80-0.60\\0.40x=1.20\\x=3\ gal

therefore

3 gallons of pure acid should be mixed with 3 gallons of a 20% acid solution in order to get a 60% acid solution

User Ben Darnell
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