The Brady family received 1 letter on July 28.
Explanation:
Step 1:
Assume a = the number of letters, b = the number of bills, c = the number of ads, and d = the number of magazines.
From the question, they got 15 pieces of mail that day so
![a+b+c+d=15.](https://img.qammunity.org/2021/formulas/mathematics/middle-school/17lr74o665v00e90za72s1on6gttzw0t81.png)
They got 5 more magazines than bills so
![d = b + 5.](https://img.qammunity.org/2021/formulas/mathematics/middle-school/gbnvkqpuh6c9k7udm2bhfp9f1195957efp.png)
The got the same number of letters as ads so
![a=c.](https://img.qammunity.org/2021/formulas/mathematics/middle-school/rh0iybzk1kktuzydk6o31c4knpv34r9zvi.png)
They got 3 more bills than ads so
![b= c + 3.](https://img.qammunity.org/2021/formulas/mathematics/middle-school/jqr9y3xt3uw51ww4qoucnmn0cp77fcv2rf.png)
Step 2:
As we have only one equation to solve the values, we need to make every term in terms of a single term.
We make everything in terms of c.
So
![a=c, b = c+3, c=c, d = b+5 = (c+3)+5=c+8.](https://img.qammunity.org/2021/formulas/mathematics/middle-school/hofuudz9xklpcwh0jtiwxgvhhkf6dotlvw.png)
Substituting all this in the equation, we get
![a + b+c+d =(c)+(c+3)+(c)+(c+8) = 15, 4c+11=15.](https://img.qammunity.org/2021/formulas/mathematics/middle-school/nquocdpv9xopdjdgwsb1q94mfwsl868g08.png)
![4c=4, c = 1.](https://img.qammunity.org/2021/formulas/mathematics/middle-school/27832bawb6g216cdwlb71rj95d2s567dya.png)
Step 3:
Substituting c = 1 in other terms, we get
![a=c=1,](https://img.qammunity.org/2021/formulas/mathematics/middle-school/qgpz23fccan5qbxx2x97kw68x8s2py6j85.png)
![b=c+3=1+3=4,](https://img.qammunity.org/2021/formulas/mathematics/middle-school/coh2wz9kwu8xvqgjmvavbq6ysjfcfev2m3.png)
and
![d = c+8 = 1+8=9.](https://img.qammunity.org/2021/formulas/mathematics/middle-school/qtn6yoxmgst7foozi8czgwkdowkafywrew.png)
As a = 1, they received 1 letter that day.