Question

26. The graph of linear function fpasses through the point (1,-6) and has a slope of -2

Answer 1

For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

`y = mx + b`

Where:

m: It is the slope of the line

b: It is the cut point with the y axis

We have according to the data:

`m = -2`

Thus, the equation is of the form:

`y = -2x + b`

We substitute the given point:

`(x, y) :( 1, -6)\\-6 = -2 (1) + b\\-6 = -2 + b\\-6 + 2 = b\\b = -4`

Finally, the equation is:

`y = -2x-4`

Answer:

`y = -2x-4`

Answer 2

`y=-2x-4`

Explanation:

step 1

Write the linear equation in point slope form

`y-y1=m(x-x1)`

we have

`m=-2\\(x1,y1)=(1,-6)`

substitute

`y+6=-2(x-1)`

step 2

Convert to slope intercept form

`y=mx+b`

we have

`y+6=-2(x-1)`

isolate the variable y

`y+6=-2x+2`

`y=-2x+2-6\\y=-2x-4`