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An ideally efficient air conditioner keeps the room air at 290 K when the outdoor air is at 305 K. How much work does it consume when delivering 900 J of heat outside?
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An ideally efficient air conditioner keeps the room air at 290 K when the outdoor air is at 305 K. How much work does it consume when delivering 900 J of heat outside?

User Simon Charette
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1 Answer

3 votes

Answer:

44.26 J

Step-by-step explanation:

Efficiency=
1-\frac {T_i}{T_h} where in this case
T_i is 290 K and
T_h is 305 hence

Efficiency=
1-\frac {290}{305}=0.04918

We also know that efficiency is given by
\frac {W}{Q_h}\\0.04918=\frac {W}{900}

W=0.04918*900=44.26 J

User Gpresland
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