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If f(1)=4f(1)=4 and f(n)=f(n-1)^2+4f(n)=f(n−1) +4 then find the value of f(3)f(3).

1 Answer

4 votes

Answer:

404

Explanation:

Use the recursive formula until you get to the term you want.

f(1) = 4

f(2) = f(1)^2 +4 = 4^2 +4 = 20

f(3) = f(2)^2 +4 = 20^2 +4 = 404

User Nirav Tukadiya
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