Question

{40x+3y=10
{ 20x−7y=5

System of equatio
Please explain

Answer 1

x =
`(1)/(4)`, y = 0

Explanation:

Given the 2 equations

40x + 3y = 10 → (1)

20x - 7y = 5 → (2)

Multiplying (2) by - 2 and adding to (1) will eliminate the x- term

- 40x + 14y = - 10 → (3)

Add (1) and (3) term by term, that is

17y = 0 ⇒ y = 0

Substitute y = 0 into either of the 2 equations and solve for x

Substituting y = 0 in (1)

40x + 3(0) = 10, that is

40x = 10 ( divide both sides by 40 )

x =
`(10)/(40)` =
`(1)/(4)`