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A. Complete the chart based on the initial conditions:

An ant population starts at 1200 for a certain colony. As each month goes by in the winter, 6.5% of the population dies off. How many of the ants should be alive after 4 months? (Round to the whole ant.)

Month Ant Population
(start) 1200
1
2
3
4



B. Consider the following table that describes the mass of a kitten as weeks go by. If you know the kitten grows by 10% each week for the first 5 weeks, fill in the table for the values each week.

Week Mass (grams)
(start) 80
1
2
3
4

1 Answer

4 votes

Answer:

a.


Month\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Pop(whole \ ant)\\month1 => x_1=80*0.94^1=1128\\month2=>x_2=1200*0.94^2=1060\\month3=>x_3=1200*0.94^3=996\\month4=>x_4=1200*0.94^4=936

b.


week Number\ \ \ \ \ \ \ \ \ \ \ \ \ \ Mass(g)\\week1 => x_1=80*1.1^1=88g\\week2=>x_2=80*1.1^2=96.8g\\week3=>x_3=80*1.1^3=106.48g\\week4=>x_4=80*1.1^4=117.128g

Explanation:

a. From the information provided, we can deduce that the population death's follows a Geometric sequence in the form
(a,ar,ar^2,ar^3...) where
a-first \ term and
r-common \ ratio

#Since the population is reducing,
r can is obtained as
r=1-r=0.94

#The
n^t^h term is obtained using the formula
x_n=ar^(^n^-^1^), given a=1200

The number of ants alive after every month (in first 4 months)


Month\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Pop(whole \ ant)\\month1 => x_1=80*0.94^1=1128\\month2=>x_2=1200*0.94^2=1060\\month3=>x_3=1200*0.94^3=996\\month4=>x_4=1200*0.94^4=936

The ant's alive after 4 months is obtained as the value of
x_5


x_n=ar^(^n^-^1^)\\1-x_5=1-1200* 0.94^4=936.89\\\approx 936

Hence, 936 ants are alive after 4 months.

b. As with the above question, the kitten population follows a geometric sequence:
(a,ar,ar^2,ar^3...).

#Since it's a growing population , the common ration is the sum of 100% + the growth rate,


r=1.1 and
a=80 and
x_n=ar^(^n^-^1^)

The population after 4weeks will be:


week Number\ \ \ \ \ \ \ \ \ \ \ \ \ \ Mass(g)\\week1 => x_1=80*1.1^1=88g\\week2=>x_2=80*1.1^2=96.8g\\week3=>x_3=80*1.1^3=106.48g\\week4=>x_4=80*1.1^4=117.128g

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