Answer:
[Na+] = 0.1528 M
[S^2-] = 0.0764 M
Step-by-step explanation:
Step 1: Data given
MAss of Na2S = 5.96 grams
Volume of solution = 1.00 L
Molar mass Na2S = 78.045 g/mol
Step 2: Calculate moles Na2S
Moles Na2S = Mass Na2S / molar mass Na2S
Moles Na2S = 5.96 grams / 78.045 g/mol
Moles Na2S = 0.0764 moles
Step 3: Calculate moles ions
For 1 mol Na2S we have 2 moles Na+ and 1 mol S^2-
For 0.0764 moles Na2S we have 0.0764 moles S^2- and 2*0.0764 = 0.1528 moles Na+
Step 4: Calculate concentration of ions
[Na+] = 0.1528 moles / 1 L = 0.1528 M
[S^2-] = 0.0764 moles / 1L = 0.0764 M