Question

they told him that he was 30.8% too low in the boiling point he had just recorded. He had recorded a boiling point of 50 degrees C on his data sheet. what is the correct boiling point of the liquid he was working with in lab?

Answer 1

To correct the 30.8% underestimation in boiling point recorded as 50°C, 15.4°C is added to the initial value, resulting in a correct boiling point of 65.4°C for the liquid.

Step-by-step explanation:

The student recorded a boiling point of 50 degrees Celsius which was 30.8% too low. To find the correct boiling point, we need to calculate the amount by which the boiling point was underestimated and then add this value to the recorded boiling point.

The calculation is as follows:
30.8% of 50°C = 0.308 × 50°C = 15.4°C.
Then, add the underestimation to the recorded boiling point: 50°C + 15.4°C = 65.4°C. Therefore, the correct boiling point of the liquid is 65.4°C.

Answer 2

• 36ºC

Step-by-step explanation:

When you calculate percent it is important to determine the base value, because that is the denominator of your equation:

`Percent=\frac{\text{change or differece}}{base}* 100`

Here:

• difference = Correct boling point - Recorded boiling point

• base = Correct boiling point. Call it Tb

• The recorded boiling point is 50ºC

• Percent = 38% (below the correct boiling point)

Subsitute and compute:

`38=(Tb-50\ºC)/(Tb)* 100\\\\\\0.38Tb=Tb-50\ºC \\\\Tb+0.38Tb=50\ºC\\\\Tb=50\ºC/1.38\\\\Tb=36.23\ºC\approx 36\ºC` ← answer