Answer:
{ - 2, 1 }
Explanation:
To determine the values let y = 0, that is
(x + 2)(2x - 2) = 0 ← in standard form
Equate each factor to zero and solve for x
x + 2 = 0 ⇒ x = - 2
2x - 2 = 0 ⇒ 2x = 2 ⇒ x = 1
The set of values are { - 2, 1 }
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