The velocity of tennis racket after collision is 14.96m/s
Step-by-step explanation:
Given-
Mass, m = 0.311kg
u1 = 30.3m/s
m2 = 0.057kg
u2 = 19.2m/s
Since m2 is moving in opposite direction, u2 = -19.2m/s
Velocity of m1 after collision = ?
Let the velocity of m1 after collision be v
After collision the momentum is conserved.
Therefore,
m1u1 - m2u2 = m1v1 + m2v2
![v1 = ((m1-m2)/(m1+m2))u1 + ((2m2)/(m1+m2))u2](https://img.qammunity.org/2021/formulas/physics/middle-school/wgr8gbd6fqodtfxocirhxtf7anh0ll1666.png)
![v1 = ((0.311-0.057)/(0.311+0.057))30.3 + ((2 X 0.057)/(0.311 + 0.057)) X-19.2\\\\v1 = ((0.254)/(0.368) )30.3 + ((0.114)/(0.368)) X -19.2\\ \\v1 = 20.91 - 5.95\\\\v1 = 14.96](https://img.qammunity.org/2021/formulas/physics/middle-school/mpev2gaihnkyca1vjnw4gfw8o1n7wshv0e.png)
Therefore, the velocity of tennis racket after collision is 14.96m/s