Question

what is the X co-ordinate of vertex of parabola where equation is Y is equal to X square + bx + c =\ o​

Answer 1

x = -
`(b)/(2)`

Explanation:

Given a quadratic equation in standard form , that is

y = ax² + bx + c = 0 ; a ≠ 0

Then the x- coordinate of the vertex is

`x_(vertex)` = -
`(b)/(2a)`

x² + bx + c = 0 ← is in standard form

with a = 1, b = b, thus

`x_(vertex)` = -
`(b)/(2)`