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Find the angle made by the vector 4i+3j+5k on x axis​

User Mathijs
by
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1 Answer

4 votes

The angle formed by vector with x-axis is nearly 35°

Step-by-step explanation:

The magnitude of resultant vector in three dimension

If vector A = 4i + 3j + 5k

The calculated magnitude | A | =
√(4^2 + 3^2 + 5^2) =
√(50) = 7

If the angle formed with x-axis by this vector is α

Then cosα = x-component of vector divided by its magnitude

or cosα =
(4)/(7) = 0.57

and angle α = 35° approx

User Pankaj Verma
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4.9k points