Question

a series circuit contains two devices one with a resistance of 10 ohms and one with a resistance of 4 ohms the generator supplies a voltage of 42 volt what is the magnitude of the current​

Answer 1

Answer:3A

Step-by-step explanation:

Answer 2

current flowing through the given circuit is 3 A

Step-by-step explanation:

When the resistances are connected in series , the total resistance is the sum of individual resistances .

Thus R = R₁ + R₂

here R₁ is resistance of 10 ohms

and R₂ is resistance of 4 ohms .

Thus total resistance R = 10 + 4 = 14 ohm .

The potential difference applied = 42 volt

Thus current I =
`(Potential)/(Resistance)` =
`(42)/(14)` = 3 A

Thus current through the circuit is 3 Ampere