Answer:
Therefore,
The area of the wall that Jenny painted is 219.8 inches².
Explanation:
Given:
Jenny uses a roller to paint a wall ,
Radius of roller = r = 1.75 inches
Height of roller = h = 10 inches
To Find:
Area of wall painted in two rolls = ?
Solution:
First we will calculate Circumference of the roller,
![Circumference=2\pi r](https://img.qammunity.org/2021/formulas/mathematics/middle-school/dwxgzuy7o3864agz9cu1mo8lbf7o86xi5h.png)
Substituting the values we get
![Circumference=2* 3.14* 1.75=10.99\ inches](https://img.qammunity.org/2021/formulas/mathematics/high-school/cllweh7b1p09bslrjidm4yme4n2mkhnbh9.png)
One Roll of roller is the one full rotation of the roller and one full rotation length, is the circumference length.
![Circumference=one\ roll](https://img.qammunity.org/2021/formulas/mathematics/high-school/z5z6fg1fw6b7i5unfkb5vo7osi1llsqf2m.png)
For two roll
![Two\ roll=Twice\ Circumference](https://img.qammunity.org/2021/formulas/mathematics/high-school/tqerutl0amhaa4q77hemf07ghlrq37rwi1.png)
Substituting the values we get
![Two\ roll=2* 10.99 =21.98\ inches](https://img.qammunity.org/2021/formulas/mathematics/high-school/b6xk7f2cxwhlp6p2iuin2e1md77mcfzq8h.png)
Now,
Height of roller = h = 10 inches
Two Roll cover distance = 21.98 inches
Painted Area will be of Rectangular shape of Dimensions 21.98 inches by 10 inches.
Let Length = 21.98 inches, Width = height = 10 inches
![Area\ of\ Rectangle = Length* Width](https://img.qammunity.org/2021/formulas/mathematics/high-school/q2y7d1eym7oaaqdu9wqukbyic4vunjsfxc.png)
Substituting the values we get
![\textrm{Painted Area for two Rolls} = 21.98* 10 =219.8\ inches^(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/rhxospk34iqguzlm2v1r0hi6ks93lf00y3.png)
Therefore,
The area of the wall that Jenny painted is 219.8 inches².