Question

What is the solution to this system of equations?

4x+6y=7
3x - 2y = -12
Multiply each equation by a number that produces opposite
coefficients for x or y.
The solution is

Answer 1

The solution is
`x = (-29)/(13), y = (69)/(26)`

Solution:

Given system of equations are:

4x + 6y = 7 --------- eqn 1

3x - 2y = -12 -------- eqn 2

Let us solve the system of equations by elimination method

Multiply eqn 2 by 3

9x - 6y = -36 ----- eqn 3

Add eqn 1 and eqn 3

4x + 6y = 7

9x - 6y = -36

( + ) --------------

13x = -29

`x = (-29)/(13)`

Substitute
`x = (-29)/(13)` in eqn 1

`4( (-29)/(13)) + 6y = 7\\\\6y = 7 + (4 * 29)/(13)\\\\6y = (207)/(13)\\\\y = (69)/(26)`

Thus the solution is
`x = (-29)/(13), y = (69)/(26)`