Question

Find the equation of a line that passes the points (5, -9) and (0, -3)

Answer 1

Y=-6/5x-3

Explanation:

Lets convert these two points into slope-intercept form.

We can find the slope with the equation y2-y1/x2-x1=slope.

Insert the values into the equation.

-9-(-3)/5-0=slope

Simplify both sides.

-6/5=slope

The slope is -6/5. To complete equation, we need to find the y intercept.

The y intercept is -3. We know this because x is equal to 0 in this point.

Write it as an equation.

y=(-6/5)x+(-3)

Simplify.

The equation would be y=-6/5x-3

Hope this helps!

Answer 2

y = -6/5x - 3

Explanation:

Point Slope Form: (y - y1) = m(x - x1)

Step 1: Find Slope

m =
`(y2-y1)/(x2-x1)`

m =
`(-3 - (-9))/(0 - 5)`

m =
`(-3 + 9)/(-5)`

m =
`(6)/(-5)`

m =
`(-6)/(5)`

Step 2: Plug into Point Slope Form

(y - (-3)) = -6/5(x - 0)

y + 3 - 3 = -6/5x - 3

y = -6/5x - 3

Answer: y = -6/5x - 3