Question

An object is dropped from a small plane. As the object falls, its distance, d, above the ground after t seconds, is given by the

formula d = -1612 + 1,000. Which inequality can be used to find the interval of time taken by the object to reach the height
greater than 300 feet above the ground?
-167 +1,000 <300

Answer 1

D -16t2+1,000 > 300

Explanation:

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Answer 2

The inequality can be used to find the interval of time taken by the object to reach the height greater than 300 feet above the ground is:

`d = -16t^2 + 1000`

Solution:

The object falls, its distance, d, above the ground after t seconds, is given by the formula:

`d = -16t^2 + 1000`

To find the time interval in which the object is at a height greater than 300 ft

Frame a inequality,

`-16t^2 + 1000 > 300`

Solve the inequality

Subtract 1000 from both sides

`-16t^2 + 1000 - 1000 > 300 - 1000\\\\-16t^2 > -700`

`16t^2 < 700\\\\Divide\ both\ sides\ by\ 16\\\\t^2 < (700)/(16)\\\\Take\ square\ root\ on\ both\ sides\\\\t < \sqrt{(700)/(16)}\\\\t < \pm 6.61`

Time cannot be negative

Therefore,

t < 6.61

And the inequality used is:
`-16t^2 + 1000>300`