Proof:
Ange EBC is 96° so the angle CBA is
180 - 96 ( angles on a straight line )
So angle CBA is 84°
I think ANGLE DBC SHOULD BE CORRECTED TO ANGLE DCB
And angle DCB is 132° so the angle BCA is equal to 48°
So to find BAC angle
48 + 84 + BAC = 180 ( interior angles of a triangle)
so angle BAC is 180 - 132
Which is again 48°
So the angles BAC = BCA
Hence the sides BC = BA
so ABC triangle is isosceles ( two angles and the two sides are equal)