Answer:
A. 36 miles
B. 30 miles
Explanation:
Let x miles be the number of miles of highway and y miles be the number of miles of highway on bridges the city can build.
Part A:
For every mile of highway on land, the city needs two truckloads of asphalt and one gallon of paint, so for x miles the city needs 2x truckloads of asphalt and x gallons of paint.
For every mile of highway on bridges, the city needs one truckload of asphalt and three gallons of paint, so for y miles the city needs y trackloads of asphalt and 3y gallons of paint.
The city has 50 truckloads of asphalt, thus
![2x+y\le50](https://img.qammunity.org/2021/formulas/mathematics/high-school/xvv7qxxl41ev0gxfl1tm3vekpm1s3zmy1a.png)
The city has 80 gallons of paint, so
![x+3y\le80](https://img.qammunity.org/2021/formulas/mathematics/high-school/5qat1koih1ga5oq4q6zledi87fp99fu9u9.png)
You get the system of two inequalities:
![\left\{\begin{array}{l}2x+y\le 50\\ \\x+3y\le 80\end{array}\right.](https://img.qammunity.org/2021/formulas/mathematics/high-school/z9xbvdwhktvsa8ynt4lp6vkrng3wfbq32z.png)
Plot the solution region on the coordinate plane (see first attached diagram).
The total number of miles is
. Its maximum value is at intersection point of lines
and
. Find the coordinates of this point:
Part B:
Suppose the city is on an island and must build at least 25 miles of highway on bridges, then the city needs
trackloads of asphalt
gallons of paint
Then
trackloads of asphalt and
gallons of paint are left.
Hence,
![2x+y\le 25\\ \\x+3y\le 5](https://img.qammunity.org/2021/formulas/mathematics/high-school/9tnnpdw2d5vq2pi7ymq23s6hmwd84upvln.png)
Plot the solution region on the coordinate plane (see second attached diagram). The total number of miles is
. Its maximum value is at point (5,0), hence
and the total number of miles is
miles.