Question

15 J of work were expended moving an 18 kg block. At what velocity did the block move?

Provide step by step walkthrough

Answer 1

Answer:√(5/3)m/s

Step-by-step explanation:

Kinetic energy(ke)=15joules

Mass(m)=18kg

Velocity(v)=?

Ke=(mxv^2) ➗ 2

15=(18xv^2) ➗ 2

Cross product

(18xv^2)=15x2

18xv^2=30

Divide both sides by 18

(18xv^2)/18=30/18

v^2=5/3

v=√(5/3)

v=√(5/3)m/s

Answer 2

1.29m/s

Step-by-step explanation:

Since work and energy have same unit of measurement, then

kinetic energy of the block = 15J

M = 18kg

V =?

K.E = 1/2MV^2

V^2 = 2K.E /M

V^2 = (2 x 15)/18

Take the square root of both side

V = √[(2 x 15)/18]

V = 1.29m/s

The block moved with a velocity of 1.29m/s