Final answer:
The question asks for Lewis formulas for the reactants and product involved in the reaction of atomic nitrogen and nitric oxide. The Lewis structure for atomic nitrogen is :N. with an unpaired electron, and for nitric oxide, it is :N=O. with an unpaired electron. The product NNO's Lewis structure is :N=N-O:, with all electrons paired.
Step-by-step explanation:
The question pertains to the combination of free radicals to form a stable molecule without any unpaired electrons. Specifically, the question asks for the Lewis formulas for the reactants and products in the reaction N (g) + NO (g) → NNO (g), including nonbonding electrons.
For the reactants, we have atomic nitrogen (N), which has five valence electrons. As a radical, it would be represented as :
N
. (the dot representing an unpaired electron). Nitric oxide (NO), as an odd-electron molecule, has a total of 11 valence electrons, and its Lewis structure can be represented as :
N=O
., showing a double bond between nitrogen and oxygen and one unpaired electron on nitrogen.
The product NNO is a molecule where both nitrogen atoms are bonded to the central oxygen atom. To achieve a stable configuration, a reasonable Lewis structure would be :
N=N-O
: with a double bond between the two nitrogen atoms and a single bond between the second nitrogen and oxygen. All electrons are now paired, reflecting the stability of the NNO molecule.