Question

Refrigerant-134a is throttled from the saturated liquid state at 800 kPa to a pressure of 140 kPa. Determine the temperature drop during this process and the final specific volume of the refrigerant.

Answer 1

The temperature drop is 61.1 °C

The final specific volume of the refrigerant is 1.236 m^3/kg

Step-by-step explanation:

Initial pressure of refrigerant = 800 kPa = 800/100 = 8 bar

Final pressure of refrigerant = 140 kPa = 140/100 = 1.4 bar

From steam table

At 8 bar, initial saturated temperature is 170.4 °C

At 1.4 bar, final saturated temperature is 109.3 °C

Temperature drop = initial saturated temperature - final saturated temperature = 170.4 - 109.3 = 61.1 °C

Also, from steam table

At 1.4 bar, specific volume is 1.236 m^3/kg

Final specific volume of the refrigerant is 1.236 m^3/kg