Question

Eva and Dulcina have 82 pins together. Dulcina has 34 more pins than Eva. How many pins are in Dulcina's collection? How many pins are in Eva's collection?

Answer 1

Answer: there are 58 pins in Dulcina's collection and 24 pins in Eva's collection

Explanation:

Let x represent the number of pins in Dulcina's collection.

Let y represent the number of pins in Eva's collection.

Eva and Dulcina have 82 pins together. This means that

x + y = 82- - - - - - - - - - - - - - - 1

Dulcina has 34 more pins than Eva. This means that

x = y + 34

Substituting x = y + 34 into equation 1, it becomes

y + 34 + y = 82

2y + 34 = 82

2y = 82 - 34

2y = 48

y = 48/2

y = 24

x = y + 34 = 24 + 34

x = 58

Answer 2

Dulcina's collection has 57 pins

Eva's collection has 25 pins

Explanation:

first we are going to represent the relation of pins by means of an equation

d = Dulcina

e = Eva

e + d = 82

and now we represent the relation of the collections of each one

d = e + 32

having the 2 equations we can replace the d by (e + 32) and place it in the other equation

e + d = 82

e + (e + 32) = 82

2e + 32 = 82

2e = 82 - 32

2e = 50

e = 25

Now we replace e with 25 in the second equation and get the value of d

d = e + 32

d = 25 + 32

d = 57