Question

A ball is thrown horizontally from a point 24m above the ground strikes the ground after travelling horizontally a distance of 18m with what speed vo was it thrown?

Answer 1

Answer:8.14 m/s

Step-by-step explanation:

Given

height from which ball is thrown is
`h=24\ m`

horizontal distance moved by ball
`x=18\ m`

suppose
`u_x` is the speed by which ball is thrown horizontally

thus

vertical distance traveled in time t is given by

`h=ut+(1)/(2)at^2`

`24=0=(1)/(2)gt^2`

`t=\sqrt{(2* 24)/(9.8)}`

`t=2.21\ s`

horizontal distance is given by

`R=u_x* t`

`18=u_x* 2.21`

`u_x=8.14\ m/s`