Question

A certain capacitor is charged to a potential difference V. If you wish to increase its stored energy by 77%, by what percentage should you increase V

Answer 1

Step-by-step explanation:

Below is an attachment containing the solution.

Answer 2

33%

Step-by-step explanation:

Energy stored in a capacitor (U) =
`1/2CV^2`

The capacitance is constant. Hence,
`(U_2)/(U_1) = (V_2^2)/(V_1^2)`

V2/V1 =
`\sqrt{(U_2)/(U_1) }`

If U1 = 1, then U2 is an increase of 77% (0.77), hence U2 = 1.77

V2/V1 =
`\sqrt{(1.77)/(1) }`

V2/V1 = 1.33

Hence, the v of the capacitor should be increased by 33% in order to increase its stored energy by 77%.