Question

What is the change in entropy of helium gas with total mass 0.130 kg at the normal boiling point of helium when it all condenses isothermally to liquid helium? Assume that the normal boiling point of helium is 4.216 K and the heat of vaporization of helium is 2.09×104 J/kg .

Answer 1

ΔS = - 645 J/K

Step-by-step explanation:

The entropy change for a phase change is given by

ΔS = ΔH phase change / T

For our question we will use this expression for the condensation of Helium:

ΔScondensation = ΔH condensation / Tb

where ΔH condensation is the change in enthaly of condensation which is the negative of the enthalpy of vaporization, and Tb is the boiling temperature in Kelvin which is the same for condensation.

We can see we are in position to plug the values in and solve for ΔScondensation :

For 0.130 kg Helium we will have

ΔHcondensation = - 0.130 Kg x 2.09 x 10⁴ J/Kg = -2.72 x 10³ J

ΔH is negative since heat is released (exothermic) during condensation.

ΔS = ΔH phase change / T = -2.72 x 10³ J / 4.216 K = - 645 J/K