Question

The concentration of dye in Solution A is 25.527 M. You have 13 mL of water at your disposal to make the dilutions. The solution is diluted twice, to make Solutions B and C. In the first dilution, 8 parts of Solution A is diluted with 12 parts water to make Solution B. In the second dilution, 8 parts of Solution B is diluted with 4 parts water to make Solution C. What is the concentration of dye in Solution C

Answer 1

The concentration of dye in Solution C is approximately 6.8298 M.

Step-by-step explanation:

In the first dilution, 8 parts of Solution A is diluted with 12 parts water to make Solution B. This means that for every 8 mL of Solution A, 12 mL of water is added. So, if you have 13 mL of water available, you can add 8 mL of Solution A and 12 mL of water to make Solution B.

In the second dilution, 8 parts of Solution B is diluted with 4 parts water to make Solution C. This means that for every 8 mL of Solution B, 4 mL of water is added. So, if you have 13 mL of water available, you can add 8 mL of Solution B and 4 mL of water to make Solution C.

To calculate the concentration of dye in Solution C, we need to consider the dilution factor. The dilution factor for Solution B is 8/20 = 0.4, and the dilution factor for Solution C is 8/12 = 0.67.

Since the concentration of dye in Solution A is 25.527 M, the concentration of dye in Solution B is 25.527 M × 0.4 = 10.2108 M, and the concentration of dye in Solution C is 10.2108 M × 0.67 ≈ 6.8298 M.

Answer 2

38825.472 M

Step-by-step explanation:

Using

C1V1=C2V2

To make solution B,

C1 = 25.527 M, V1 = 13 mL

C2 = 25.527 x 8 = 204.216 M

V2 = 13 X 12 = 156 mL

To make solution C'

C1 = 8 X 202.216 M = 1617.728

V1 = 8 X 156mL = 1248 mL

V2 = 4 X 13 = 52 mL

C2 = C1V1 / V2

=1617.728 X 1248 / 52

=38825.472 M