Question

asked Nov 6, 2021 125k views

2 Answers

Lgersman · Answer 1 · 2021-11-06T22:48:04+0000

Answer:

a)
$\lambda=5* 10^6\ m$

b) The wavelength of the obtained is greater than 1mm so it lies in the range of radio waves.

c)
$B_m=3.867* 10^(-5)\ T$

Step-by-step explanation:

Given:

frequency of electromagnetic waves,
$f=60\ Hz$

maximum field strength of the electric field,
$E_m=11600\ V.m^(-1)$

Since the velocity of electromagnetic waves is,
$c=3* 10^8\ m.s^(-1)$

a)

We know the relation between the frequency and wavelength is given as:

$\lambda=(c)/(f)$

$\lambda=(3* 10^(8))/(60)$

$\lambda=5* 10^6\ m$

b)

The wavelength of the obtained is greater than 1mm so it lies in the range of radio waves.

c)

The maximum magnetic field can be calculated as:

B_m=(E_m)/(c)

B_m=(11600)/(3* 10^8)

$B_m=3.867* 10^(-5)\ T$

Ikaver · Answer 2 · 2021-11-09T22:12:35+0000

Step-by-step explanation:

Given that,

Frequency of the power line, f = 6 Hz

Value of maximum electric field strength of 11.6 kV/m

(a) The wavelength of this very low frequency electromagnetic wave is given by using relation as :

$c=f\lambda$

$\lambda=(c)/(f)$

$\lambda=(3* 10^8\ m/s)/(60\ Hz)$

$\lambda=5* 10^6\ m$

(b) As its can be seen that the wavelength of this wave is very high. It shows that it is a radio wave.

(c) The relation between the maximum magnetic field strength and maximum electric field strength is given by :

$B_0=(E_0)/(c)\\\\B_0=(11.6* 10^3)/(3* 10^8)\\\\B_0=3.86* 10^(-5)\ T$

So, the maximum magnetic field strength is
$3.86* 10^(-5)\ T$ .

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