Question

In horses, the gene for black coat color is dominant over the gene for brown coat color. The gene for long manes is dominant over the gene for short manes. After a cross is made between a homozygous black, long mane mare (BBLL)and a stallion homozygous for brown color and short mane (bbll), and the F1 offspring are interbred, the expected outcome in the F2 for a brown, long mane horse would be

Answer 1

answer is 3/16

Step-by-step explanation:

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Answer 2

3/16

Step-by-step explanation:

Given,

Black coat color is dominant over brown coat color.

Long mane is dominant over short mane.

BBLL X bbll =

F1: BbLl = Entire progeny has black color and long mane

BbLl progeny will produce BL, Bl, bL and bl gametes. When they interbreed, the resultant F2 progeny will be in 9:3:3:1 dihybrid ratio. Hence in F2,

BBLL : BbLL : bbLl : bbll = 9 : 3 : 3 : 1

3/16 progeny will have bbLl genotype hence 3/16 progeny will have brown, long mane.