Question

Complete and balance the molecular equation, including phases, for the reaction of aqueous copper (ll) chloride, CuCl2, and aqueous potassium phosphate, K3PO4.

Cu Cl,(aq) K,PO4(aq) -->

Enter the balanced net ionic equation, including phases, for this reaction

Answer 1

`3{Cu^2^+}(aq.) + 2{PO_4^3^+}(aq)` ⇒
`Cu_3(PO)_4`

Step-by-step explanation:

Reaction Type

It is double displacement reaction.

Cupric Chloride + Tribasic Potassium Phosphate ⇒ Cupric Phosphate + Potassium Chloride

Reactants

1. Cupric Chloride
   `(CuCl_2)`
2. Tribasic Potassium Phosphate
   `(K_3PO_4)`

Products

1. Cupric Phosphate
   `(Cu_3(PO_4)_2)`
2. Potassium Chloride
   `(KCl)`

The reaction is as follows -

`CuCl_2 + K_3PO_4` =
`Cu_3(PO_4)_2 + KCl`

∴ The Balanced Chemical Equation is as follows -

`3CuCl_2 + 2K_3PO_4` =
`Cu_3(PO_4)_2 + 6KCl`

The Net ionic equation including the phases is as follows -

`3{Cu^2^+}(aq.) + 2{PO_4^3^+}(aq)` ⇒
`Cu_3(PO)_4`