Answer:
B) vector of the form (2,r, (2-5r)/4)
Explanation:
(2,b,c) is orthogonal to (1,-5,-4) if
2*1-5b-4c=0, i.e,
5b+4c=2
We have equation with two variables, so we know that we wil have infinity lot solutions.
Let’s b be some real number r, so we have:
4c=2-5r, i.e,
c=(2-5r)/4.
So there is infinite lot of othogonal vectors of the form: (2, r, (2-5r)/c)) where r is any real number.