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If the work done to stretch an ideal spring by 4.0 cm is 6.0 J, what is the spring constant (force constant) of this spring? A) 300 N/m B) 3000 N/m C) 3500 N/m D) 7500 N/m E) 6000 N/m

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Answer:

D) 7500 N/m

Step-by-step explanation:

Given :

Work done by the spring, W = 6 J

Stretch in the spring, x = 4 cm = 0.04 m

Consider k be the spring constant.

The relation between work done and stretch of the spring is:


W=(1)/(2)kx^(2)

Substitute the suitable values in the above equation.


6=(1)/(2)k(0.04)^(2)


k=(12)/(1.6*10^(-3) )

k = 7500 N/m

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