Answer:
D) 7500 N/m
Step-by-step explanation:
Given :
Work done by the spring, W = 6 J
Stretch in the spring, x = 4 cm = 0.04 m
Consider k be the spring constant.
The relation between work done and stretch of the spring is:
![W=(1)/(2)kx^(2)](https://img.qammunity.org/2021/formulas/physics/college/s4odd5jd8cp9xrdmau9ubn4mvsbtg7vspn.png)
Substitute the suitable values in the above equation.
![6=(1)/(2)k(0.04)^(2)](https://img.qammunity.org/2021/formulas/physics/college/8ykw5tmbt7406qql83d1hj5hpz7355sqfq.png)
![k=(12)/(1.6*10^(-3) )](https://img.qammunity.org/2021/formulas/physics/college/47gawcltsp4rb4s8omf3lb1p3073ygeuhi.png)
k = 7500 N/m