Question

A survey of athletes at a high school is conducted, and the following facts are discovered: 29% of the athletes are football players, 63% are basketball players, and 24% of the athletes play both football and basketball. An athlete is chosen at random from the high school: what is the probability that he is either a football player or a basketball player?

Answer 1

i think the is A ian a hundun percent correct bye itch

Explanation:

Answer 2

The probability that he is either a football player or a basketball player is
`(11)/(25)`.

Explanation:

29% athletes are football players and 24% of the athletes are both football and basketball player.

Hence, (29 - 24) = 5% athletes are football player but not basketball player.

Similarly, (63 - 24) = 39% athletes are basketball player but not a football player.

Hence, the required probability is
`(5 + 39)/(100) = (44)/(100) = (11)/(25)`.