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Black fur in mice (B) is dominant to brown fur (b). Short tails (T) are dominant to long tails (t). What fraction of the offspring of crosses BbTt × BBtt will be expected to have black fur and long tails?

User Misman
by
3.0k points

2 Answers

2 votes

Answer:

the answer is a, 1/2

Step-by-step explanation:

User Dooburt
by
3.6k points
4 votes

Answer:

1/2 or 50%

Step-by-step explanation:

B is dominant over b and T is dominant over t.

BbTt is crossed with BBtt

BbTt x BBtt = 4 BBTt, 4 BBtt, 4 BbTt and 4 Bbtt

4 BBTt = black fur with short tail

4 BBtt = Black fur with long tail

4 BbTt = Black fur with short tail

4 Bbtt = Black fur with long tail.

8 of the offpring have black fur with long tail while 8 also have black fur with short tail.

The proportion of offspring having black fur with long tail is 1/2 or 50%.

User ZixiCat
by
3.8k points