Question

A wire loop of radius 0.37 m lies so that an external magnetic field of magnitude 0.35 T is perpendicular to the loop. The field reverses its direction, and its magnitude changes to 0.19 T in 1.3 s. Find the magnitude of the average induced emf in the loop during this time.

Answer 1

0.053V

Step-by-step explanation:

Average induced emf is given as:

EMF(avg) = (ΔB * A)/t

Change in magnetic field strength, ΔB= 0.35 - 0.19 = 0.16T

Area, A = 3.142*r² = 3.142 * 0.37²

A = 0.43 m²

EMF(avg) = (0.16 * 0.43) / 1.3

EMF(avg) = 0.053 V