Question

In an isochoric process, the pressure in a system changes from 10 kPa to 20 kPa at V= 5m3. Calculate the work done in this process according to the sign convention in the class.

Answer 1

work done in the process is 0 J.

Step-by-step explanation:

Given :

Initial pressure of system ,
`p_i=10\ kPa.`

Final pressure of system ,
`p_f=20\ kPa.`

Volume of system ,
`V=5\ m^3.`

We know, In thermodynamics work done is defined as :

`W=P\Delta V`

Here , P is pressure and
`\Delta V` is change in volume.

Now, coming back to question , it state that the process is isochoric .

Therefore, change in volume ,
`\Delta V=0.`

Putting value of
`\Delta V=0` in above equation we get ,

W = 0 J.

Therefore , work done in this process is 0 J.

Hence, this is the required solution.